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x^2+5x-9=31
We move all terms to the left:
x^2+5x-9-(31)=0
We add all the numbers together, and all the variables
x^2+5x-40=0
a = 1; b = 5; c = -40;
Δ = b2-4ac
Δ = 52-4·1·(-40)
Δ = 185
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{185}}{2*1}=\frac{-5-\sqrt{185}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{185}}{2*1}=\frac{-5+\sqrt{185}}{2} $
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